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NEET Class neet Answered

Formula to be applied is  → Heat loss = heat gain Ms(T1-T2)... Doubt :- plzz explain T1 and T2 in each case.
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Asked by jhajuhi19 | 23 Jun, 2019, 12:36: AM
answered-by-expert Expert Answer
Thermal energy gained by vessel with contents = Water Equivalent×Specific heat×rise in temperature
                                                                            = 200×10-3×4200×(40-10) Joules
                                                                             = 25200 Joules
 
Hence Thermal energy lost by ball of thermal capacity 10 cal/°C =  10×4.2×(Tf - 40) Joules
                                                                                                     = 42×(Tf - 40) Joules
Where Tf is initial temperature of ball before dropping to the vessel and it is equal to temperature of furnace.
 
By conservation of energy, Gain of thermal energy by the vessel and its contents is equal to loss of thermal energy by ball .
 
hence, 42×(Tf - 40) = 25200  or  Tf = 640 °C
Answered by Thiyagarajan K | 23 Jun, 2019, 09:38: AM
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