NEET Class neet Answered
Formula to be applied is
→ Heat loss = heat gain
Ms(T1-T2)...
Doubt :- plzz explain T1 and T2 in each case.
Asked by jhajuhi19 | 23 Jun, 2019, 12:36: AM
Expert Answer
Thermal energy gained by vessel with contents = Water Equivalent×Specific heat×rise in temperature
= 200×10-3×4200×(40-10) Joules
= 25200 Joules
Hence Thermal energy lost by ball of thermal capacity 10 cal/°C = 10×4.2×(Tf - 40) Joules
= 42×(Tf - 40) Joules
Where Tf is initial temperature of ball before dropping to the vessel and it is equal to temperature of furnace.
By conservation of energy, Gain of thermal energy by the vessel and its contents is equal to loss of thermal energy by ball .
hence, 42×(Tf - 40) = 25200 or Tf = 640 °C
Answered by Thiyagarajan K | 23 Jun, 2019, 09:38: AM
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