Please wait...
Contact Us
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry



Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

9372462318 / 9987178554

Mon to Sat - 10 AM to 7 PM

Forces F1, F2, and F3 are acting on a particle of mass m such that F2 are F3 are mutually perpendicular.It is observed that the particle remains stationary.If force F1 is removed then acceleration of the particle is....

Asked by sandhyamsani 22nd March 2017, 8:25 PM
Answered by Expert
When forces F1, F2 and F3 are acting on the particle, it remains in equilibrium. Now, it is given that F2 and F3 are perpendicular to each other. So, we can infer that force F1 has to balance the resultant of the other two forces.
begin mathsize 12px style straight F subscript 1 equals straight F subscript 2 perpendicular straight F subscript 3
therefore straight F subscript 1 equals square root of straight F subscript 2 superscript 2 plus straight F subscript 3 superscript 2 end root end style
The force F1 is now removed. So, the resultant of F2 and F3 will now make the particle move with force equal to F1. Hence, the acceleration of the particle is
begin mathsize 12px style straight a equals straight F subscript 1 over straight m end style
Answered by Expert 24th March 2017, 6:39 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Free related questions

Chat with us on WhatsApp