NEET Class neet Answered
force of attraction between a and b in this slope
Asked by preetijaiswalpj9 | 20 Feb, 2021, 11:09: AM
Expert Answer
Due to the application of force F whole system moves with acceleration a and block B of mass m does not slip.
Figure shows the forces acting on block B . Weight mg is acting downwards. Force of interaction between A and B is the
Normal reaction force. Normal reaction force R due wedge A acting perpendicular to the inclined surface of wedge.
As shown in figure, Normal reaction force R can be resolved as Rcosθ and Rsinθ .
Resolved component Rcosθ balances the weight mg , While Rsinθ accelerate the block B .
R cosθ = m g
R sinθ = m a
Hence, we get 
Answered by Thiyagarajan K | 21 Feb, 2021, 08:04: PM
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