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Force and laws of motion

Asked by docben 26th September 2009, 7:49 PM
Answered by Expert
Answer:

Net accelerating force,F=Force due to engine- Frictional force=40000-5000=35000 N

The acceleration of train,a=F/M=35000/18000=35/18=1.87 ms-2

 

friction force on the four wagons=8000/18000 * 5000=20000/9 N

Let the required force be F'.

F'-20000/9=(800)(35/18)

or F'=        (14000+20000)/9=34000/9=3777.77 N

 

Answered by Expert 18th October 2009, 12:54 AM
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