CBSE Class 9 Answered
Force and laws of motion
Asked by docben | 26 Sep, 2009, 07:49: PM
Expert Answer
Net accelerating force,F=Force due to engine- Frictional force=40000-5000=35000 N
The acceleration of train,a=F/M=35000/18000=35/18=1.87 ms-2
friction force on the four wagons=8000/18000 * 5000=20000/9 N
Let the required force be F'.
F'-20000/9=(800)(35/18)
or F'= (14000+20000)/9=34000/9=3777.77 N
Answered by | 18 Oct, 2009, 12:54: AM
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