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for what value of k does the eqution has real and equal roots? x+2x+(k)(k)+1=0

Asked by 28th February 2013, 11:20 AM
Answered by Expert
Answer:
Can you please again check your equation, does it mean  x2+2x+k2+1=0  ?
 
If yes, then for equal and real roots D = 0
i.e. b2 - 4ac = 0
i.e. (2)2 - 4(1) (k2+1) = 0
4 - 4k2-4 = 0
i.e. k = 0
 
 
Answered by Expert 28th February 2013, 5:05 PM
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