Contact

For Enquiry

10:00 AM to 7:00 PM IST all days.

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

8788563422

Mon to Sat - 10 AM to 7 PM

# For the circuit, if capacitor is shorted,then what is amplitude of output voltage in mA?A)0 B)25 C)50 D)75 C)100

Asked by miaowmira1900 24th January 2020, 5:30 PM
It is assumed point-C in the circuit is at ground potential. As shown in figure, after shorting the capacitor,
let us assume at junction B, current i1 is getting divided as i2 and i3.

For the line, A-B-C, if we write kirchoff's voltage law,   300(i1 + i3) = 5  ..................(1)

For the line A-B-E, neglecting 100 mV ac voltage source, we have,  300 i1 + 150 i2 + 4 = 5 ............(2)

At junction B,  we have ,  i1 = i2 + i3   ......................(3)

By solving above equations, we get i3 = 10.3 mA

Hence output voltage = 10.3 mA × 300 Ω = 3.09 V
Answered by Expert 25th January 2020, 9:53 AM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer 10/10

Tags: voltage

### Free related questions

20th May 2018, 5:36 PM
10th June 2018, 8:48 AM
RELATED STUDY RESOURCES :