CBSE Class 12-science Answered
For radiation of wavelength lambda,the stoping potential is 3v0 and for 2 lambda, the stoping potential is v0.find the threshhold wavelength
Asked by Parasbir99 | 11 Nov, 2018, 07:02: AM
Expert Answer
Einstein's photoelectric equation :-
where ν is the frequency of incident electro-magnetic radiation, w is the workfuction in energy units and
this workfunction is the characterstic of photoelectric material.
Second term of LHS of eqn.(1) is the kinetci energy of ejected electron.
Eqn.(1) can be rewritten in terms of wavelength of incident radiation and by replacing the workfunction as
the equivalent threshold wavelength λth . Kinetic energy also can be replaced by stopping potential V.
Hence the modified equation is,
if we substitute the given data in eqn.(2), we get the following equations.
By solving eqns.(3) and (4) for λth , we get λth = 4λ
Answered by Thiyagarajan K | 11 Nov, 2018, 09:25: AM
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