For given common emitter configuration of n–p–n transistor with β = 100, the minimum input voltage such that transistor comes in saturation region is [Given VBE = 0.8 volt]
Asked by dipanshusingla029
22nd May 2018,
1:32 PM
Answered by Expert
Answer:
Collector current IC for saturation condition is given by :- IC = VCC / RC
where VCC is applied DC voltage across Collector-to-Emitter through load resistance RC .
In the given figure VCC = 20 V and RC = 10 kΩ. Hence IC = 20/10K = 2 mA .
Base current IB = IC / β = 2 mA /100 = 20μA .
Input voltage VBB is given by VBB = IB×RB +VBE ; where RB is the resistance connected between base and input bias voltage
VBB= 20×10-6×200×1000 + 0.8 = 4.8 V
Answered by Expert
22nd May 2018,
4:48 PM
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