For a reaction A↽−−⇀B, the activation energy for the forward reaction is 65 kJ mol−1. If enthalphy of reaction is 42 kJ mo1−1, the activation energy for the raction B⟶A would be?
Asked by imtiyazmulla68
12th April 2018,
11:38 PM
Answered by Expert
Answer:
Given:
Eaf = 65 kJ/mole
ΔH = 42 kJ/mole
Ear = ?
We have,
ΔH = Eaf - Ear
Ear = Eaf - ΔH
= 65 - 42
= 23 kJ/mole
Activation energy of the reaction B⟶A is 23 kJ/mole.
Answered by Expert
16th April 2018,
12:59 PM
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