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CBSE Class 10 Answered

Five years ago , fathers age was 2 times the sum of ages of his three children. after 5 years fathers age can be obtained by subtracting 8 from the sum of ages of the three children. fathers present age is?
Asked by drpatilsm | 14 May, 2019, 10:19: PM
answered-by-expert Expert Answer
 
 
Let the present age of father be x years and sum of ages of his three children be y years.
 
Five years ago , fathers age was 2 times the sum of ages of his three children.
 
→  (x - 5) = 2(y - 15)
→   x - 2y= - 25   ... (i)
 
After 5 years fathers age can be obtained by subtracting 8 from the sum of ages of the three children. 
 
→  (x + 5) = (y +15 - 8)
→         x - y   =  2   ... (ii)
 
Subtracting (ii) from (i), we get
 y = 27
 
Put y = 27 in (ii), we get
 
x = 29 
 
Therefore the present age of father is 29 years. 
Answered by Yasmeen Khan | 15 May, 2019, 09:13: AM

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