CBSE Class 8 Answered
Five years ago,a mother was seven times as old as her daughter.Five years hence,she will be three times as old as her daughter.Find their present ages
Asked by shrabaninayak27 | 19 Feb, 2019, 01:14: PM
Expert Answer
Let Present age of mother = x years and present age of daughter = y years
5 years ago : mother was (x-5) years, daughter was (y-5), it is given (x-5) = 7(y-5) or x-7y = -30 ...................(1)
5 years hence : mother will be (x+5) years, daughter will be (y+5) years, it is given (x+5) = 3(y+5) or x-3y = 10 ...........(2)
By solving eqn.(1) and (2), we get x = 40, y = 10
Hence present ages of mother and daughter are 40 years and 10 years respectively
Answered by Thiyagarajan K | 19 Feb, 2019, 01:40: PM
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