JEE Class main Answered
Find velocity and distance
Asked by asjadhav2003 | 24 Mar, 2020, 09:43: PM
Expert Answer
Position vector as function of time t is given by, 
........................(1)
........................(1)at t = 0, we have 
= 0 i.e. starting position,
= 0 i.e. starting position, we see that when t = 1/a , we get = 0 , i.e., starting point is reached at t = 1/a
= 0 , i.e., starting point is reached at t = 1/avelocity d/dt is obtained by differentiating eqn.(1), d/dt = 
.....................(2)
/dt is obtained by differentiating eqn.(1), d/dt = .....................(2)velocity when it is returning to statring point is obtained by substituting, t = 1/a , i.e., d/dt = - 
/dt = - It can be seen from eqn.(2) , initially velocity starts with at t = 0 , then keep on decreasing, becoming zero at t = 1/(2a),
at t = 0 , then keep on decreasing, becoming zero at t = 1/(2a),reversing the direction afterwards and finally reaches the starting point with velocity - .
.position vector at t=1/2a is given by, = / (4a)
= / (4a)Distance covered with negative velocity is also same . Hence total distance covered = / (2a)
/ (2a)
Answered by Thiyagarajan K | 25 Mar, 2020, 08:27: AM
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