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Find Value Of 2.Sec2[Square]180[Degree].Cos0[Degree]+3Sin3[Cube]270[Degree]+Cosec90[Degree]

Asked by chethan U 23rd July 2012, 6:35 PM
Answered by Expert
Answer:
2 sec2180 . cos0 + 3 sin3270 + cosec 90
= 2 sec2(90 + 90) . 1 + 3 sin3(180 + 90) + 1
= 2 cosec2 90 . 1 - 3 sin3 90 + 1
= 2 - 3 + 1
= 0

Answered by Expert 23rd July 2012, 10:30 PM
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