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CBSE Class 11-science Answered

Find the variation of acceleration due to gravity below the surface of earth at depth'd'  
Asked by mz05022003 | 24 Feb, 2020, 08:13: PM
answered-by-expert Expert Answer
Now, consider a point mass m at a depth d below the surface of the earth as shown in figure, so
that its distance from the center of the earth is ( RE − d ) as shown in the figure. The earth can
be thought of as being composed of a smaller sphere of radius (RE – d ) and a spherical shell
of thickness d. The force on m due to the outer shell of thickness d is zero.
 
 As far as the smaller sphere of radius ( RE – d ) is concerned, the point mass is outside it and hence according
to the result quoted earlier, the force due to this smaller sphere is just as if the entire mass of the smaller sphere
is concentrated at the centre.
 If Ms is the mass of the smaller sphere, then,  
 
begin mathsize 14px style M subscript S over M subscript E space equals space fraction numerator open parentheses R subscript E minus d close parentheses cubed over denominator R subscript E superscript 3 end fraction end style ................................(1)
 
Equation (1) is written because mass of a sphere is proportional to be cube of its radius.
 
Thus the force on the point mass at a depth d from earth surface is
 
begin mathsize 14px style F left parenthesis d right parenthesis space equals space G fraction numerator M subscript s space m over denominator open parentheses R subscript E minus d close parentheses squared end fraction end style  .........................(2)
 
Substituting for Ms from eqn.(1) , we rewrite eqn.(2) as
 
begin mathsize 14px style F left parenthesis d right parenthesis space equals space G fraction numerator M subscript E space m over denominator R subscript E superscript 3 space end fraction left parenthesis R subscript E minus d right parenthesis end style .........................(3)
 
Using the definition of acceleration due to gravity g on earth surface , begin mathsize 14px style g space equals space G space fraction numerator M subscript E over denominator R subscript E superscript 2 end fraction end style  ,
we get acceleration due to gravity at a depth d from eqn.(3) as
 
 
g(d) = Force/mass = g [ 1 - ( d / RE ) ]
 
 Thus, as we go down below earth’s surface, the acceleration due gravity decreases by a factor [ 1 - ( d / RE ) ]

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