CBSE Class 10 Answered
Find the values of k for which the given equation has real and equal roots:
2x2-10x+k=0.
Asked by Topperlearning User | 07 Nov, 2013, 10:55: AM
Expert Answer
The given quadratic equation is 2x2-10x+k=0.
Here, a=2, b=-10 and c=k
Therefore, D=b2-4ac = (-10)2 - 4x2xk = 100-8k
The equation will have real and equal roots, if
D=0 100-8k = 0 K==
Answered by | 07 Nov, 2013, 12:55: PM
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