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Find the values of k for which the given equation has real and equal roots:

2x2-10x+k=0.


Asked by Topperlearning User 7th November 2013, 10:55 AM
Answered by Expert
Answer:

The given quadratic equation is 2x2-10x+k=0.

Here, a=2, b=-10 and c=k

Therefore, D=b2-4ac = (-10)2 - 4x2xk = 100-8k

The equation will have real and equal roots, if

D=0 100-8k = 0  K==


Answered by Expert 7th November 2013, 12:55 PM
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