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Home / Doubts and Solutions/JEE/Mathematics

Find the value of x?

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Asked by ac5744100 26th July 2018, 9:14 PM
Answered by Expert
Answer:
log 0.5 (x2 - 5x + 6) > -1
x2 - 5x + 6 > 0.5-1 
begin mathsize 16px style straight x squared space minus space 5 straight x space plus space 6 space greater than space fraction numerator 1 over denominator 0.5 end fraction rightwards double arrow 0.5 straight x squared minus 2.5 straight x plus 3 greater than 1 rightwards double arrow straight x squared minus 5 straight x plus 4 greater than 0 rightwards double arrow left parenthesis straight x minus 4 right parenthesis left parenthesis straight x minus 1 right parenthesis greater than 0 straight x space element of left parenthesis negative infinity comma 1 right parenthesis union left parenthesis 4 comma infinity right parenthesis end style
Answered by Expert 27th July 2018, 9:52 AM
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