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Find the value of k for which the roots of this equation are real and equal k^2 x^2 - 2(2k-1)x + 4= 0 

Asked by Ashutosh 21st February 2018, 7:51 PM
Answered by Expert
Answer:
begin mathsize 16px style straight k squared straight x squared minus 2 open parentheses 2 straight k minus 1 close parentheses straight x plus 4 equals 0
According space to space the space question
straight D equals 0
open square brackets negative 2 open parentheses 2 straight k minus 1 close parentheses close square brackets squared minus 4 straight k squared cross times 4 equals 0
4 open parentheses 4 straight k squared minus 4 straight k plus 1 close parentheses minus 16 straight k squared equals 0
16 straight k squared minus 16 straight k plus 4 minus 16 straight k squared equals 0
minus 16 straight k plus 4 equals 0
16 straight k equals 4
straight k equals 1 fourth end style
Answered by Expert 22nd February 2018, 9:33 AM
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