CBSE Class 10 Answered
Find the value of k for which 2k +
7, 6k - 2 and 8k + 4 form 3
consecutive terms of an AP.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
We know that three terms p,q,r form consecutive terms of AP if and only if 2q = p+r
Thus, 2k + 7, 6k - 2 and 8k + 4 will form consecutive terms of an AP is 2(6k-2) = (2k+7) + (8k+4)
Now, 2(6k-2) = (2k+7) + (8k+4)
12k - 4 = 10k + 11
2k = 15
k =
Answered by | 04 Jun, 2014, 03:23: PM
Application Videos
Concept Videos
CBSE 10 - Maths
Asked by rrajansinghakb199 | 08 Apr, 2024, 05:12: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by goyelgurav | 18 Dec, 2023, 11:23: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by mehraharshit.dk000 | 05 Oct, 2023, 08:05: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by atharvsharma971 | 06 Jun, 2022, 10:30: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by ankur.spsharma | 02 May, 2022, 11:54: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by iambkhatun343 | 14 Feb, 2022, 12:57: AM
ANSWERED BY EXPERT