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Find the sum of all three digit number which when divided by 16 leaves remainder 7?

Asked by 9th June 2008, 1:12 PM
Answered by Expert
Answer:

The first such 3 digit number is 103 and the last such number is 999.

The terms in between form an AP with a common difference of 16.

Find the number of terms, n using the relation 999 = 103+16(n-1)

Find the sum using the relation Sn = n/2[a+l]

Answered by Expert 24th June 2008, 5:42 PM
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