Gujarat Class 10 Answered
Find the sum of all three digit natural numbers divisible by 3
Asked by kvdudhaiya | 16 Jan, 2019, 02:08: PM
Expert Answer
sum = ( 3+6+9+.......+999) = 3×(1+2+3.....+333)
sum = ( 3×333×334)/2 = 3×333×167 = 166833
( sum of n natural numbers ,i.e, 1+2+3 .....n, is n(n+1)/2 )
Answered by Thiyagarajan K | 16 Jan, 2019, 03:01: PM
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