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ICSE Class 10 Answered

Find the result of mixing 10 g of ice at -10οC with 10 g of water at 10οC.Specific heat capacity of ice=2.1 J g-1 K-1, specific latent heat of ice=336 J g-1 and specific heat capacity of water=4.2 J g-1K-1.
Asked by Prameela | 13 Feb, 2018, 09:55: PM
answered-by-expert Expert Answer
Finally some ice will melt and become water and the whole mixture will reach a temperature of 0ºC.
 
let x gm of ice will melt.
 
heat energy gained by ice = (x×2.1×10 + x×336 ) J
 
heat energy lost by water = 10×4.2×10 = 420 J
 
since heat loss of ice equals heat gain of water, x × (21+336) = x × 357 = 420
 
hence we get x = 1.176 g
 
hence final mixture is 11.176 g of water + 8.824 g of ice and the mixture is at temperature of 0ºC.
Answered by Thiyagarajan K | 14 Feb, 2018, 12:30: PM

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