Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739
For Business Enquiry

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

FIND THE RANGE

Asked by vk1994 28th April 2010, 12:09 PM
Answered by Expert
Answer:

Dear student,

the solution of your quesry is as follows -

Since (y-1) is there in the denominator, therefore x will tend to infinity when y=1. So, x will not be defined at y=1. => y ≠ 1.

Also, for x to be real, (9y2-11-6y) must be greater than or equal to 0.

therefore,

We note that (1+121/2)/3 > 1,

therefore the range of y is .

Answered by Expert 28th April 2010, 4:03 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp