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Find the percentage composition of carbon,hydrogen and oxygen in glucose

Asked by 25th February 2013, 1:49 PM
Answered by Expert
Answer:
Atomic weight:
Carbon = 12.01
Hydrogen = 1.01
Oxygen = 16.00

Work out the molecular weight of glucose
= (6 x 12.01) + (12 x 1.01) + (6 x 16.00)
= 72.06 + 12.12 + 96.00 
= 180.18

The percentages are then derived from the weight of the individual elements:

Carbon = 72.06 / 180.18 x 100 = 40.0%
Hydrogen = 12.12 / 180.18 x 100 = 6.7% 
Oxygen = 96.00 / 180.18 x 100 = 53.3%
Answered by Expert 25th February 2013, 6:18 PM
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