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CBSE Class 11-science Answered

find the number of quanta of radiation of frequency 4.75* 10 sec inverse required to melt 100 g of ice the energy  required to melt 1 g of ice is 350 joule  
Asked by sejalchawhan8 | 29 Aug, 2018, 09:07: PM
answered-by-expert Expert Answer
 
 
 
We space know space that comma

Enargy space of space one space photon space straight E space equals space nhν

straight nu space equals 4.75 cross times space 10 to the power of 13 space sec to the power of negative 1 end exponent space

straight h equals space 6.62 cross times 10 to the power of negative 34 end exponent space straight J. straight s

straight E space equals space straight n cross times 4.75 cross times space 10 to the power of 13 space cross times space space 6.62 cross times 10 to the power of negative 34 end exponent

straight E space equals straight n cross times 31.445 cross times 10 to the power of negative 21 end exponent space straight J space space space space space space space space space space space space space space space space space space space................... open parentheses 1 close parentheses

Energy space required space to space melt space 1 space straight g space of space ice space is space 350 space straight J

Energy space required space to space melt space 100 space straight g space of space ice space equals 350 cross times 100

Energy space required space to space melt space 100 space straight g space of space ice equals 35000 space straight J space space space space........ space space open parentheses 2 close parentheses

From space eq space open parentheses 1 close parentheses space and space open parentheses 2 close parentheses

straight n cross times 31.45 cross times 10 to the power of negative 21 end exponent space equals space space 35000 space

space space space space space space space space space space space space space space space space space space space space space space space space straight n space equals fraction numerator 35000 space over denominator 31.445 cross times 10 to the power of negative 21 end exponent end fraction

space space space space space space space space space space space space space space space space space space space space space space space space straight n space equals 1113 space cross times 10 to the power of 21
Quanta of radiations is 1113 × 1021 .
 
 
 
 
Answered by Varsha | 30 Aug, 2018, 11:57: AM
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