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CBSE Class 9 Answered

Find the missing frequencies f1 and f2 in the following frequency distribution, if it is known that the mean of the distribution is 1.46 x1 0 1 2 3 4 5 Total f1 46 f1 f2 25 10 5 200  
Asked by Topperlearning User | 09 Dec, 2013, 10:52: AM
answered-by-expert Expert Answer

xi 

fi

fixi­

0

46

0

1

f1

f1

2

f2

2f2

3

25

75

4

10

40

5

5

25

N = 86 + f1 + f2

We have N = 200

200 = 86 + f1­ + f2

Thus, f1 = 114 - f2    .....(i)

Mean = 1.46

292 = 140 + f1 + 2f2

f1 + 2f2 = 152  .....(ii)

Solving (i) and (ii), we get

114 - f2 + 2f2 = 152

Thus, f2 = 38

Hence, f1 = 114 - 38 = 76

Answered by | 09 Dec, 2013, 12:52: PM
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