CBSE Class 9 Answered
Find the missing frequencies f1 and f2 in the following frequency distribution, if it is known that the mean of the distribution is 1.46
x1
0
1
2
3
4
5
Total
f1
46
f1
f2
25
10
5
200
Asked by Topperlearning User | 09 Dec, 2013, 10:52: AM
Expert Answer
xi |
fi |
fixi |
0 |
46 |
0 |
1 |
f1 |
f1 |
2 |
f2 |
2f2 |
3 |
25 |
75 |
4 |
10 |
40 |
5 |
5 |
25 |
N = 86 + f1 + f2
We have N = 200
200 = 86 + f1 + f2
Thus, f1 = 114 - f2 .....(i)
Mean = 1.46
292 = 140 + f1 + 2f2
f1 + 2f2 = 152 .....(ii)
Solving (i) and (ii), we get
114 - f2 + 2f2 = 152
Thus, f2 = 38
Hence, f1 = 114 - 38 = 76
Answered by | 09 Dec, 2013, 12:52: PM
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