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# Find the missing frequencies f1 and f2 in the following frequency distribution, if it is known that the mean of the distribution is 1.46 x1 0 1 2 3 4 5 Total f1 46 f1 f2 25 10 5 200

Asked by Topperlearning User 9th December 2013, 10:52 AM

 xi fi fixi­ 0 46 0 1 f1 f1 2 f2 2f2 3 25 75 4 10 40 5 5 25

N = 86 + f1 + f2

We have N = 200

200 = 86 + f1­ + f2

Thus, f1 = 114 - f2    .....(i)

Mean = 1.46

292 = 140 + f1 + 2f2

f1 + 2f2 = 152  .....(ii)

Solving (i) and (ii), we get

114 - f2 + 2f2 = 152

Thus, f2 = 38

Hence, f1 = 114 - 38 = 76

Answered by Expert 9th December 2013, 12:52 PM
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