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Find the missing frequencies f1 and f2 in the following frequency distribution, if it is known that the mean of the distribution is 1.46

x1

0

1

2

3

4

5

Total

f1

46

f1

f2

25

10

5

200

 

Asked by Topperlearning User 9th December 2013, 10:52 AM
Answered by Expert
Answer:

xi 

fi

fixi­

0

46

0

1

f1

f1

2

f2

2f2

3

25

75

4

10

40

5

5

25

N = 86 + f1 + f2

We have N = 200

200 = 86 + f1­ + f2

Thus, f1 = 114 - f2    .....(i)

Mean = 1.46

292 = 140 + f1 + 2f2

f1 + 2f2 = 152  .....(ii)

Solving (i) and (ii), we get

114 - f2 + 2f2 = 152

Thus, f2 = 38

Hence, f1 = 114 - 38 = 76

Answered by Expert 9th December 2013, 12:52 PM
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