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CBSE Class 9 Answered

Find the length of 2 m wide tarpaulin required to make conical tent of height 6 m and base diameter 16 m?
Asked by Topperlearning User | 17 Oct, 2017, 09:42: AM
answered-by-expert Expert Answer

Given: Diameter = 16 m

 Radius (r) = 8 m, height (h) = 6 m

Let slant height = l

begin mathsize 12px style l squared space equals space straight r squared space plus space straight h squared l space space equals space square root of straight r squared space plus space straight h squared end root space l italic space italic space equals square root of 8 squared space plus space 6 squared end root l italic space italic space equals 10 space cm Thus comma space l italic space equals space 10 space cm Curved space surface space area space equals space πr l italic space equals 22 over 7 cross times 8 cross times 10 equals space 1760 over 7 space straight m squared end style

Breadth of tarpaulin (B) = 2 m, let length of tarpaulin = L

Area of tarpaulin required = curved surface area of the tent

begin mathsize 12px style straight L space cross times space straight B space equals space 1760 over 7 straight L space equals space fraction numerator 1760 over denominator 7 cross times 2 end fraction straight L space equals space 880 over 7 straight L space equals space 125.7 space straight m space left parenthesis Approx. right parenthesis end style

 

Area of tarpaulin required is 125.7 m 

Answered by | 17 Oct, 2017, 11:42: AM

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