CBSE Class 6 Answered
Find the greatest number which divides 203and 434 leaving remainder 5in each
Asked by Nishugupta7517 | 22 Aug, 2019, 07:04: PM
Expert Answer
The numbers that are exactly divisible are 203 - 5 = 198 and 434 - 5 = 429 as leaving remainder 5 in each.
Prime factorization of 198 = 2 × 3 × 3 × 11
Prime factorization of 429 = 3 × 11 × 13.
HCF(198, 429) = 3 × 11
= 33.
Therefore the largest number which divides 203 and 434 leaving remainder 5 in each case = 33.
Prime factorization of 198 = 2 × 3 × 3 × 11
Prime factorization of 429 = 3 × 11 × 13.
HCF(198, 429) = 3 × 11
= 33.
Therefore the largest number which divides 203 and 434 leaving remainder 5 in each case = 33.
Answered by Sneha shidid | 23 Aug, 2019, 09:57: AM
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