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# find the energy lost by the capacitor

Asked by 22nd February 2008, 11:55 PM

The formula for Energy lost after connecting two capacitors with rating C1,V1 and c2,v2 respectively

When the two capacitors are connected, charge will be redistributed between the two capacitors so that the potential across both of them is the same.

HERE,Given C1=4uf, v1=80v and   C2=6uf  , v2=30v..putting the values we can find the energy lost.

Find charge on each capacitor using q = CV; Then find total charge which is q1 + q2= C1 V1 + C2 V2.

This charge will be redistributed between the two capacitors so that the potential across both is same

V1 = V2

q1/C1 = q2/C2 so q1/q2 = C1/C2 = 4/6

Here q1 = 2/5(q)

Similarly q2 = 3/5(q)

So the charge on each capacitor can be found, C of each capacitor is known, If V is found it will be same for both capacitors. Then energy can be found using 1/2CV^2 and loss in energy can also be found.

Answered by Expert 19th April 2008, 4:44 PM
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