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Find the distance of the point (2, 5) from the line 4 (x + 5) = 7 (2y - 3).

Asked by Topperlearning User 29th April 2014, 3:09 PM
Answered by Expert
Answer:

The given line is

            4 (x + 5) = 7 (2y - 3)

        4x + 20 = 14y - 21

        4x - 14y + 20 + 21 = 0

        4x - 14y + 41 = 0
The perpendicular distance from (x1, y1) to the line ax + by + c = 0 is

.

The point (x1, y1) is (2, 5).

Perpendicular distance from (2, 5) to the line 4x - 14y + 41 = 0 is

Answered by Expert 29th April 2014, 5:09 PM
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