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find the density of rubber

Asked by neha khan 30th September 2013, 11:36 PM
Answered by Expert
Answer:

Let 'g' be the acceleration due to gravity

      'p' be the density of water, so, p = 1 g/cm 

      'V' be the volume of the ball

      'q' be the density of the ball

Volume of ball within water = V (1V/3)

                                             = (2V/3)

                                             = Volume of water displaced by the ball

Weight of the water displaced = (2V/3) p g

Weight of the ball = V q g

Since, the ball is floating

(2V/3) p g = V q g

=> q = (2/3) x p

=> q= (2/3) x 1

Therefore, the density of the cork is (2/3) g/cm 3

 

Answered by Expert 1st October 2013, 8:29 AM
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