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CBSE Class 12-science Answered

Find the de-Broglie wavelength associated with neutrons in thermal equilibrium with matter at 300K. 
Asked by sahupramod650 | 14 Nov, 2019, 11:32: AM
answered-by-expert Expert Answer
neutron energy at thermal equilibrium = 0.025eV
 
deborglie wavelength λ = h/(mv) = h /(2Em)1/2 ...............(1)
 
where h is plancks constant, h = 6.626 × 10-34 Js-1 ,
E is energy , E = 0.025 eV = 0.025 × 1.602 × 10-19 J
m is mass of neutron = 1.675 × 10-27 kg
 
Using all the above values in eqn.(1), we get λ = (6.626×10-34) / (2 × 0.025 ×1.602 × 10-19 ×1.675 × 10-27 )
deborglie wavelength λ = 1.81 × 10-10 m
 
 
Answered by Thiyagarajan K | 14 Nov, 2019, 12:43: PM

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