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Find the capacitance of A and B
 

Asked by nikitaayyagari 17th May 2016, 7:40 AM
Answered by Expert
Answer:

Hi Nikita, 

The top left corner capacitors of 2mF are connected in series with each other,

the right bottom corner capacitors of 4mF are also connected in series with each other,

the above two combinations are further connected in parallel with the middle 2mF capacitor branch.

capacitors in series are given bybegin mathsize 12px style 1 over straight C equals space 1 over straight C subscript 1 space plus space 1 over straight C subscript 2
therefore space 1 over straight C space equals space 1 half space plus space 1 half
therefore space 1 over straight C space equals space 1 over 1
bold therefore bold C bold space bold equals bold space bold 1 bold space bold mF

Similarly space the space equivalent space capacitance space of space the space bottom space right space corner space 4 mF space capacitors space is space given space by
space 1 over straight C equals space 1 over straight C subscript 1 space plus space 1 over straight C subscript 2
space 1 over straight C equals space 1 fourth space plus space 1 fourth
space 1 over straight C equals space 1 half
bold therefore bold C bold space bold equals bold space bold 2 bold space bold mF

The space above space two space capacitors space are space further space connected space in space parallel space with space the space middle space 2 mF space capacitor
their space equivalent space capacitance space is space given space by
straight C space equals space straight C subscript 1 plus straight C subscript 2 plus straight C subscript 3
straight C space equals space 1 space plus space 2 space plus space 2
straight C space equals space 5 mF
bold Therefore bold space bold the bold space bold equivalent bold space bold capacitance bold space bold between bold space bold point bold space bold A bold space bold and bold space bold B bold space bold is bold space bold 5 bold mF end style 



Answered by Expert 6th June 2016, 6:33 PM
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