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# Find the area & perimeter of a rhombus whose diagonals measure 28cm and 96cm.

Asked by Cl_narayan 30th September 2019, 9:38 PM
The diagonals of a rhombus are 28 cm and 96 cm.
Area of rhombus = 1/2 of product of diagonals = 1/2 × 28 × 96 = 1344 cm2
The diagonals are perpendicular bisectors of each other.
In triangle AOB,
using Pythagoras
AO2 + OB2 = AB2
482 + 142 = AB2
AB2 = 2500
AB = 50 cm
The side of a rhombus is 50 cm.
Perimeter of a rhombus = 50 × 4 = 200 cm
Answered by Expert 1st October 2019, 9:30 AM
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