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CBSE Class 9 Answered

Find the area of a triangle whose side are respectively 150 cm, 120 cm and 200 cm
Asked by digantverma08 | 14 Aug, 2015, 02:14: PM
answered-by-expert Expert Answer
begin mathsize 14px style T h e space s i d e s space o f space t h e space t r i a n g l e space a r e space a comma space b comma space c. a space equals space 150 space c m b space equals space 120 space c m c space equals space 200 space c m s space equals space fraction numerator a space plus space b space plus space c over denominator 2 end fraction equals fraction numerator 150 space plus space 120 space plus space 200 over denominator 2 end fraction equals 470 over 2 equals 235 B y space H e r o n apostrophe s space f o r m u l a comma A r e a space equals space A space equals square root of s left parenthesis s minus a right parenthesis left parenthesis s minus b right parenthesis left parenthesis s minus c right parenthesis end root space A space equals square root of 235 left parenthesis 235 minus 150 right parenthesis left parenthesis 235 minus 120 right parenthesis left parenthesis 235 minus 200 right parenthesis end root A space equals square root of 235 cross times 85 cross times 115 cross times 35 end root A space equals square root of 235 cross times 85 cross times 115 cross times 35 end root A space equals square root of 5 cross times 47 cross times 5 cross times 17 cross times 5 cross times 23 cross times 5 cross times 7 end root A space equals 25 square root of 47 cross times 17 cross times 23 cross times 7 end root A space equals 25 square root of 128639 space c m squared end style
Answered by Kajal Gupta | 14 Aug, 2015, 04:29: PM

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