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ICSE Class 9 Answered

Find the area of a trapezium whose parallel sides are 55 cm, 40 cm and non-parallel sides are 20 cm and 25 cm.
Asked by Topperlearning User | 29 Aug, 2017, 12:08: PM
answered-by-expert Expert Answer



begin mathsize 12px style Draw space DP space parallel to AD space so space as space to space complete space the space parallel to space gm space ABPD BP equals AD equals 20 space cm DP equals AB equals 40 space cm PC equals DC minus DP equals 55 minus 40 equals 15 space cm In space increment BPC straight S equals fraction numerator straight a plus straight b plus straight c over denominator 2 end fraction equals fraction numerator 25 plus 15 plus 20 over denominator 2 end fraction equals 30 space cm Area space of space increment BPC space equals square root of straight S open parentheses straight S minus straight a close parentheses open parentheses straight S minus straight b close parentheses open parentheses straight S minus straight c close parentheses end root space equals square root of 30 open parentheses 30 minus 25 close parentheses open parentheses 30 minus 15 close parentheses open parentheses 30 minus 20 close parentheses end root equals square root of 22500 equals 150 space sq. space cm equals 1 half cross times base cross times altitude equals 1 half cross times PC cross times straight h 150 equals 1 half cross times 15 cross times straight h straight h equals 20 space cm Area space of space parallelogram equals 1 half cross times open parentheses AB plus DC close parentheses cross times straight h equals 1 half cross times open parentheses 40 plus 55 close parentheses cross times 20 equals 950 space sq. space cm end style

Answered by | 29 Aug, 2017, 02:08: PM

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