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Asked by 16th February 2009, 6:04 PM
Answered by Expert

Charge Q will be same on both the capacitors that are in series.

For capacitor A

Q = C1(40V )

For capacitor B

Q = C2(60V)

So C1/C2 = 3/2

C1 = 3x and C2 = 2x

On connecting 6 microfarad with B the potential drop is equal to that across A, so the capacitance of this combination is equal to the capacitance of A.

Now you can write an equation in variable x and solve it to find C1 and C2.

Answered by Expert 17th February 2009, 3:38 PM
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