Find moment of inertia of the half solid cylinder of mass M shown in fig about the axis AA.
Asked by m.nilu
19th October 2018,
12:53 AM
Answered by Expert
Answer:
Moment of inertia of the given half-cylinder about the axix OO' is M×(R2/4).
M is mass of half-cylinder.
By parallel axis theorem, Moment of inertia of the given half-cylinder about the axix AA' is M×(R2/4) + M×R2= (5/4)M×R2
Answered by Expert
19th October 2018,
5:45 AM
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