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CBSE Class 11-science Answered

Find integration.
question image
Asked by dineshchem108 | 10 Aug, 2018, 09:49: PM
answered-by-expert Expert Answer
begin mathsize 16px style straight I equals integral subscript 0 superscript 1 fraction numerator dx over denominator square root of straight x plus 1 end root plus square root of straight x end fraction
straight I equals integral subscript 0 superscript 1 fraction numerator dx over denominator square root of straight x plus 1 end root begin display style plus end style begin display style square root of straight x end style end fraction cross times fraction numerator square root of straight x plus 1 end root minus square root of straight x over denominator square root of straight x plus 1 end root minus square root of straight x end fraction
straight I equals integral subscript 0 superscript 1 open parentheses square root of straight x plus 1 end root minus square root of straight x close parentheses dx
straight I equals open square brackets fraction numerator left parenthesis straight x plus 1 right parenthesis to the power of begin display style 3 over 2 end style end exponent over denominator begin display style 3 over 2 end style end fraction minus fraction numerator straight x to the power of begin display style 3 over 2 end style end exponent over denominator begin display style 3 over 2 end style end fraction close square brackets subscript 0 superscript 1
straight I equals 2 over 3 open parentheses 2 to the power of 3 over 2 end exponent minus 1 minus 1 close parentheses
straight I equals fraction numerator begin display style 2 end style over denominator begin display style 3 end style end fraction open parentheses 2 to the power of fraction numerator begin display style 3 end style over denominator begin display style 2 end style end fraction end exponent minus 2 close parentheses end style
Answered by Sneha shidid | 13 Aug, 2018, 11:07: AM

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