CBSE Class 12-science Answered
find how many grams of KCL should be added to 1 kg of water to lower its freezing point to -8 degree celsius( kf =1.86 K Kg/ mol) pls explain each and every step
Asked by ppratim02 | 10 Jul, 2016, 07:27: PM
Expert Answer
KCl dissociate in water completely hence i=2
∆Tf = i Kf x m
m= ∆Tf/i Kf
m= 8 / 2X1.86 = 2.15mol/kg.
Grams of KCl= 2.15 X 74.5 = 160.2 g/kg ( Molar mass of KCl = 74.5g/mol)
Answered by Vaibhav Chavan | 10 Jul, 2016, 09:21: PM
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