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CBSE Class 10 Answered

Find HCF of no.s 1405,1465,1530 by euclids division algorithm  
Asked by nitikaassar | 27 Jun, 2019, 12:52: PM
answered-by-expert Expert Answer
Here 1530 > 1465
1530 = 1465 × 1 + 65
1465 = 65 × 22 + 35
   65  =  35 × 1 + 30
   35  =  30 × 1 + 5
   30  =   5 × 6 + 0
 
HCF(1465, 1530) = 5
 
Here 1405 > 5
1405 = 5 × 281 + 0

HCF(1405, 5)= 5
 
Therefore HCF(1405,1465,1530)= 5
Answered by Yasmeen Khan | 27 Jun, 2019, 03:54: PM
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