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CBSE Class 12-science Answered

find dy/dx x = cos-1 1/ ( 1 + t2)1/2      y = sin-1 t/(1 + t2)1/2 explain in great detail  
Asked by haroonrashidgkp | 24 Aug, 2018, 10:50: PM
answered-by-expert Expert Answer
begin mathsize 16px style straight x equals cos to the power of negative 1 end exponent open parentheses fraction numerator 1 over denominator square root of 1 plus straight t squared end root end fraction close parentheses
straight t equals tanθ rightwards double arrow straight theta equals tan to the power of negative 1 end exponent straight t
straight x equals cos to the power of negative 1 end exponent open parentheses fraction numerator 1 over denominator square root of 1 plus tan squared straight theta end root end fraction close parentheses
straight x equals cos to the power of negative 1 end exponent open parentheses 1 over secθ close parentheses
straight x equals cos to the power of negative 1 end exponent open parentheses cosθ close parentheses
straight x equals straight theta
straight x equals tan to the power of negative 1 end exponent straight t
dx over dt equals fraction numerator 1 over denominator 1 plus straight t squared end fraction............. left parenthesis straight i right parenthesis
straight y equals sin to the power of negative 1 end exponent open parentheses fraction numerator straight t over denominator square root of 1 plus straight t squared end root end fraction close parentheses
straight t equals tanθ rightwards double arrow straight theta equals tan to the power of negative 1 end exponent straight t
straight y equals sin to the power of negative 1 end exponent open parentheses fraction numerator straight t anθ over denominator square root of 1 plus tan squared straight theta end root end fraction close parentheses
straight y equals sin to the power of negative 1 end exponent open parentheses fraction numerator begin display style fraction numerator sinθ over denominator cos straight theta end fraction end style over denominator secθ end fraction close parentheses
straight y equals sin to the power of negative 1 end exponent open parentheses sinθ close parentheses
straight y equals straight theta
straight y equals tan to the power of negative 1 end exponent straight t
dy over dt equals fraction numerator 1 over denominator 1 plus straight t squared end fraction............ left parenthesis ii right parenthesis
From space left parenthesis straight i right parenthesis space and space left parenthesis ii right parenthesis
dy over dx equals 1 end style
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Asked by haroonrashidgkp | 24 Aug, 2018, 10:50: PM
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Asked by haroonrashidgkp | 24 Aug, 2018, 10:50: PM
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