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CBSE Class 12-science Answered

  find dy/dx when x =(sin 2 thita )1/2 and y = (cos 2 thita)1/2 explain in great detail
Asked by haroonrashidgkp | 13 Aug, 2018, 09:05: PM
answered-by-expert Expert Answer
begin mathsize 16px style straight x equals square root of sin 2 straight theta end root
dx over dθ equals fraction numerator 1 over denominator 2 square root of sin 2 straight theta end root end fraction cross times 2 cos 2 straight theta
dx over dθ equals fraction numerator cos 2 straight theta over denominator square root of sin 2 straight theta end root end fraction........... left parenthesis straight i right parenthesis
straight y equals square root of cos 2 straight theta end root
dy over dθ equals fraction numerator 1 over denominator 2 square root of cos 2 straight theta end root end fraction cross times negative 2 sin 2 straight theta
dy over dθ equals fraction numerator sin 2 straight theta over denominator square root of cos 2 straight theta end root end fraction............... left parenthesis ii right parenthesis
dy over dx equals fraction numerator dy over dθ over denominator dx over dθ end fraction
dy over dx equals fraction numerator fraction numerator sin 2 straight theta over denominator square root of cos 2 straight theta end root end fraction over denominator fraction numerator cos 2 straight theta over denominator square root of sin 2 straight theta end root end fraction end fraction............... From space left parenthesis straight i right parenthesis space and space left parenthesis ii right parenthesis
dy over dx equals fraction numerator sin 2 straight theta over denominator square root of cos 2 straight theta end root end fraction cross times fraction numerator square root of sin 2 straight theta end root over denominator cos 2 straight theta end fraction
dy over dx equals fraction numerator sin 2 straight theta over denominator cos 2 straight theta end fraction cross times fraction numerator square root of sin 2 straight theta end root over denominator square root of cos 2 straight theta end root end fraction
dy over dx equals tan 2 straight theta square root of tan 2 straight theta end root end style
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