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Find a unit vector in the direction of the resultant of the vectors i-j+3k, 2i+j-2k and -i-j-3k.

Asked by akshitaasia 18th March 2018, 5:35 PM
Answer Verified by Expert
Answer:

Resultant of the vectors given is

(i-j+3k)+(2i+j-2k)+(-i-j-3k)

Which is equal to r= 2i-j-2k

Magnitude of r=|r|=√(2²+1²+2²)=3

Therefore the unit vectoe in the direction r is

(1/3)×(2i-j+2k)

 

Verified by Expert 18th March 2018, 6:05 PM
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