Fimd slit width
Asked by tandonyashika
3rd November 2018,
8:29 PM
Answered by Expert
Answer:
Angular spacing of central maximum in single slit pattern = 2×(λ/a) .............(1)
where λ is wavelength of light used and a is slit width.
Angular spacing of single interference fringe pattern in double slit experiment = λ/d .............(2)
where d is distance between slits.
from eqn.(1) and (2), we can calculate the slit width a for 20 maximum slit pattern as follows
20×( λ/d ) = 2×(λ/a) or a = d/10 ...............(3)
d is given as 1 mm. Hence slit width a = 0.1 mm.
Answered by Expert
5th November 2018,
1:37 AM
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