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ICSE Class 10 Answered

fig. 8.37 below shows a battery of emf 9V & internal resistance 0.6ohm, connected to three resisters A, B & C. Calculate: a) the combined resistance of B & C. b) the total resistance of A, B & C. c) the total resistance of the circuit, d) the current in each resistor A, B & C. (please explain this question with explaination as i have doubt in this one) e) the potential drop across the internal resistance, f) the potential difference across the resistor B, g) the terminal voltage of the cell.
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Asked by nethra | 04 Mar, 2018, 12:28: PM
answered-by-expert Expert Answer
(a) combined resistance of B and C which are parallel  :  (6×4)/(6+4) = 2.4Ω
 
(b) total reswistance A, B and C = 2+2.4 = 4.4
 (
(c) total resistance of the circuit = 2+2.4+0.6 = 5 (internal resistance of battery 0.6 is added)
 
 
(d) current in each resistor:-
 
current in the circuit = 9/5 =1.8 A
 
same 1.8A will flow through internal resistance, Resitor A and parallel combination of B and C.
 
Current through Resistance B = 1.8 × (6/10) = 1.08 A
Current through Resistance C = 1.8 × (4/10) = 0.72 A

(e) potential drop across inernal resistance = 0.6×1.8 = 1.08 V
 
(f) potential drop across resistor B = 1.08×4 = 4.32
 
(g) terminal voltage = 9 - 1.08 = 7.92 V
Answered by Thiyagarajan K | 04 Mar, 2018, 06:18: PM

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