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Ferric oxide crystallizes in a hexagonal close packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions.Derive the formula of the ferric oxide.

Asked by DIPTI PRIYA 12th February 2011, 5:49 PM
Answered by Expert
Answer:
Dear Student
 
Unit cell of hcp structure = 6 No. of oxide ions per unit cell = 6 No. of octahedral voids = 6 Since, ferric ions occupy only two out of every three octahedral voids, Therefore, no. of octahedral holes occupied by ferric ions = 2/3 X 6 = 4 Stoichiometric ratio of Fe and O = 4:6 = 2:3 Hence, formula of ferric oxide = Fe2O3.
 
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Answered by Expert 13th February 2011, 9:53 PM
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