CBSE Class 9 Answered
Factorize
: a3 + 8b3 - 27c2 + 18 abc.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
a3 + 8b3 - 27c2 + 18 abc
= (a)3 + (2b)3 + (-3c)3 + 18 abc
=(a)3 + (2b)3 + (-3c)3 - 3(a) (2b) (-3c)
We know that
x3 + y3 + z3 - 3xyz = (x + y + z) (x2 + y2 + z2 - xy - yz - zx)
Therefore,
(a)3 + (2b)3 + (-3c)3 - 3(a) (2b) (-3c)
= (a + 2b - 3c) (2a2 + 4b2 + 9c2 - 2ab + 6bc + 3 ac)
Answered by | 04 Jun, 2014, 03:23: PM
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