ICSE Class 9 Answered
Factorise: 9a2-(a2-4)2
Asked by girishbiswal | 25 May, 2018, 07:44: AM
Expert Answer
9a2 - (a2 - 4)2 = (3a)2 - (a2 - 4)2
= (3a + a2 - 4) [3a - (a2 - 4)]
= (a2 + 3a - 4)(3a - a2 + 4)
= (a + 4)(a - 1)(-a2 + 3a + 4)
= (a + 4)(a - 1)[-(a2 - 3a - 4)]
= - (a + 4)(a - 1) (a - 4)(a + 1)
= (a + 4)(a - 1)(a + 1)(4 - a)
Answered by Sneha shidid | 25 May, 2018, 08:53: AM
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