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CBSE Class 9 Answered

F=mv^2/r. How. 
Asked by suman04naha | 13 Aug, 2019, 07:46: PM
answered-by-expert Expert Answer
Let us consider a particle travel with constant speed from A to B in a circular path of radius r in a short time Δt
making an angular displacement Δθ as shown in figure.
 
distance S travelled is the arc length AB and it is given by,  S = v×Δt ..................(1)
 
Arc distance S also written geometrically as,   S = r×Δθ  ...........................(2)
 
from (1) and (2), we write ,  Δθ/Δt  = v/r  ...............(3)
 
Eqn.(3) is rate of angular displacement or angular velocity.
 
For small angular displacement made in short time Δt, we can write = dθ/dt = v/r  ......................(4)
 
In right side figure, velocity vectors at A and B are drawn by merging their initial points.
The angle between these vectors also Δθ.
 
from the right side figure, we write,  sin (Δθ/2) = (Δv/2) / v    or  Δv/2 = v sin(Δθ/2)  .................(5)
 
For small angle Δθ,  eqn.(5) is written as, Δv/2 = v Δθ/2   or Δv/Δθ = v   or     dv/dθ = v  .....................(6)
 
using eqn.(4) and eqn(6),    acceleration directed towards centre, dv/dt  = ( dv/dθ ) (dθ/dt) = v×(v/r) = ( v2 / r )
 
If m is mass, then   force F = mass×acceleration = m×(v2 / r )
 
Answered by Thiyagarajan K | 13 Aug, 2019, 10:50: PM
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