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Expression of magnetic field along axis of solenoid of finite length

Asked by Aditi Priya 14th December 2011, 1:08 PM
Answered by Expert
magnetic fld along the axis of solenoid is ?0nI ,where n=number of turns/length.
Just as the capacitor can be constructed to create a uniform electric field between the plates with zero field outside the region bounded by the plates, so too the long solenoid gives rise to a uniform magnetic field throughout the interior region and an exterior field that is zero. This can be seen by probing the field not only as a function of axial position but of radius as well. For the finite length solenoid, the on-axis interior field designated by H_ in Fig. 8.2.4 is given by (13) for locations on the z axis where d/2 z.



In the limit where the solenoid is also very long compared to its radius, where d/2a 1, this expression becomes



Probing of the field shows the field maintains the value and direction of (16) over the interior cross-section as well.
 the magnetic field intensity just outside the windings at an axial location that is several radii a from the coil ends is relatively small.
Answered by Expert 14th December 2011, 2:24 PM
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